Respuesta :
Answer:
[tex]T_f=44.72^{\circ}C[/tex]
1. Heat extracted from mass as given by the above equation (1) i.e. heat transfer is directly proportional to mass, temperature change and specific heat.
2. Using the equation of heat as mentioned in eq. (1) we find the value of final temperature.
3. The heat extracted from the system is taken as negative.
4. When heat is extracted from a body then its temperature can be expected to decrease.
Explanation:
Given:
- initial temperature of the iron object, [tex]T_i=72^{\circ}C[/tex]
- mass of the object, [tex]m=0.09\ kg[/tex]
- heat extracted from the object, [tex]Q=-1100\ J[/tex]
- specific heat of iron, [tex]c=448\ J.kg^{-1}.K^{-1}[/tex]
From the equation of heat:
[tex]Q=m.c.(T_f-T_i)[/tex] .......................(1)
[tex]-1100=0.09\times 448\times (T_f-72)[/tex]
[tex]T_f=44.72^{\circ}C[/tex]
1. Heat extracted from mass as given by the above equation (1) i.e. heat transfer is directly proportional to mass, temperature change and specific heat.
2. Using the equation of heat as mentioned in eq. (1) we find the value of final temperature.
3. The heat extracted from the system is taken as negative.
4. When heat is extracted from a body then its temperature can be expected to decrease.