To develop this problem we will make a diagram describing the problem. From there we will obtain the angle of the force, and quickly using Pythagoras the distance between the two points. Applying the electrostatic force formula we will find the magnitude of said force
PART A)
The direction of force is
[tex]tan \theta = \frac{2}{2}[/tex]
[tex]\theta = tan^{-1} \frac{2}{2}[/tex]
[tex]\theta = 45\°[/tex]
Therefore angle [tex]\theta[/tex] is 45° counter clockwise from +x axis
PART B)
Magnitude of force
[tex]F = \frac{kq_1q_2}{r^2}[/tex]
Here
k = Coulomb's constant
[tex]q_{1,2}[/tex] = Each charge
r = Distance
[tex]F = \frac{(9*10^{9})(40*10^{-9})(20*10^{-9})}{(\sqrt{8})^2}[/tex]
[tex]F = 900*10^{-9}N[/tex]
