Answer:
pH of the solution is 10.37
Explanation:
[tex]pOH=pkb+log\frac{[salt]}{[base]}[/tex]
kb = [tex]4.4 \times 10^{-4}[/tex]
pkb = -log kb
= [tex]-log4.4 \times 10^{-4}[/tex]
= 3.35
salt is methylammonium bromide and methylamine is base
Substitute the values in the above expression as follows:
[tex]pOH=pkb+log\frac{[salt]}{[base]} \\=3.35+log\frac{0.35}{0.18} \\=3.35+0.28\\=3.63[/tex]
pH = 14 - pOH
= 14 - 3.63
= 10.37
pH of the solution is 10.37
