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A laboratory animal exercised on a treadmill raises a 200 g mass 1.55 m, and at the same time loses 5.0 J energy as heat. Assume the animal is a closed system. How much does its internal energy change?

Respuesta :

mshahzaib247

Answer:

3.303 kJ

Explanation:

W = P.E = 200 × 1.55 × 9.8 = 3308 J

Q = - 5.0 J

ΔU = W + Q

     = 3308 + (- 5) = 3303 J or 3.303 kJ

So, the change in internal energy of laboratory animal is 3.303 kJ.

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