Respuesta :
Explanation:
The balanced reaction equation is as follows.
[tex]C_{3}H_{8} + 5O_{2} \rightarrow 4H_{2}O + 3CO_{2 }[/tex]
As it is given that 2.3 times the amount of [tex]O_{2}[/tex] is needed to drive this reaction we can calculate just how much [tex]O_{2}[/tex] we have, keeping in mind we only need 5 moles of [tex]O_{2}[/tex] .
Hence, [tex]5 moles \times 2.30[/tex] = 11.5 moles of [tex]O_{2}[/tex]
= 12 (moles approx)
Therefore, it means that [tex]C_{3}H{8}[/tex] is our limiting reagent, so product formed will be as follows.
[tex]C_{3}H_{8}[/tex] : [tex]H_{2}O[/tex] = 1:4 meaning we create 4 moles of [tex]H_{2}O[/tex]
[tex]C_{3}H_{8}[/tex] : [tex]CO_{2}[/tex] = 1:3 meaning we create 3 moles of [tex]CO_{2} [/tex]
As, in the given reaction we had 12 moles of [tex]O_{2}[/tex], but 5 moles were consumed in the reaction meaning we have:
12 - 5 = 7 moles of [tex]O_{2}[/tex]
Thus, we will add up all the moles and get the ratios for each gas as follows.
7 + 4 + 3 = 14 moles
[tex]O_{2} = \frac{7}{14} = 0.5
[tex]H_{2}O = \frac{4}{14}[/tex] = 0.285
[tex]CO_{2} = \frac{3}{14}[/tex] = 0.214
Hence, [tex]C_{3}H_{8}[/tex] will be consumed completely.
Answer:
Mol fraction of O2 = 0.482
Mol fraction of H2O = 0.296
Mol fraction of CO2 = 0.222
Explanation:
Step 1: Data given
A sample of propane (C3H8) is placed in a closed vessel together with an amount of O2 that is 2.30 times the amount needed to completely oxidize the propane
Step 2: The balanced equation
C3H8 + 5O2→4H2O + 3CO2
Step 3: Calculate moles
We have 2.30 times the amount of O2 needed to drive this reaction we can calculate just how much O2 we have, keeping in mind we only need 5 moles of O2
Moles O2 = 5 moles * 2.3 = 11.5 moles of O2
⇒ C3H8 is our limiting reagent
Mol ratio C3H8 : H2O = 1:4 meaning for each mol C3H8 consumed, we produce 4 moles H2O
Mol ratio C3H8 : CO2 = 1:3 meaning for each mol C3H8 consumed, we produce 3 moles CO2
in the reaction we had 11.5 moles of O2, but 5 moles were consumed in the reaction meaning we have:
11.5 - 5 = 6.5 moles of O2 remaining
Step 4: Calculate total moles
Total moles = 6.5 + 4 + 3 = 13.5moles
Step 5: Calculate mol fraction
O2 =6.5/13.5 = 0.482
H2O = 4/13.5 = 0.296
CO2 = 3/13.5 = 0.222