Answer:
The particle’s velocity is -16.9 m/s.
Explanation:
Given that,
Initial velocity of particle in negative x direction= 4.91 m/s
Time = 12.9 s
Final velocity of particle in positive x direction= 7.12 m/s
Before 12.4 sec,
Velocity of particle in negative x direction= 5.32 m/s
We need to calculate the acceleration
Using equation of motion
[tex]v = u+at[/tex]
[tex]a=\dfrac{v-u}{t}[/tex]
Where, v = final velocity
u = initial velocity
t = time
Put the value into the equation
[tex]a=\dfrac{7.12-(-4.91)}{12.9}[/tex]
[tex]a=0.933\ m/s^2[/tex]
We need to calculate the initial speed of the particle
Using equation of motion again
[tex]v=u+at[/tex]
[tex]u=v-at[/tex]
Put the value into the formula
[tex]u=-5.321-0.933\times12.4[/tex]
[tex]u=-16.9\ m/s[/tex]
Hence, The particle’s velocity is -16.9 m/s.
