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The nucleus of the hydrogen atom has a radius of about 1 x 10−15 m. The electron is normally at a distance of about
5.3 x 10^−11 m from the nucleus.
Assuming the hydrogen atom is a sphere with a radius of 5.3 x 10^−11 m.
Find: (a) the volume of the atom, (b) the volume of the nucleus , and (c) the percentage of the volume of the atom that is occupied by the nucleus.

Respuesta :

Answer:

(a). The volume of the atom is [tex]6.23\times10^{-31}\ m^3[/tex]

(b). The volume of the nucleus is [tex]4.18\times10^{-45}\ m^3[/tex]

(c). The percentage of the volume of the atom that is occupied by the nucleus is [tex]6.70\times10^{-13}[/tex]

Explanation:

Given that,

Radius of nucleus [tex]r_{n}=1\times10^{-15}\ m[/tex]

Radius of atom [tex]r=5.3\times10^{-11}\ m[/tex]

(a). We need to calculate the volume of the atom

Using formula of volume of the atom

[tex]V=\dfrac{4\pi\times r^3}{3}[/tex]

Where, r = radius of atom

Put the value into the formula

[tex]V=\dfrac{4\pi\times(5.3\times10^{-11})^3}{3}[/tex]

[tex]V=6.23\times10^{-31}\ m^3[/tex]

(b). We need to calculate the volume of the nucleus

Using formula of volume of the nucleus

[tex]V'=\dfrac{4\pi\times r^3}{3}[/tex]

Where, r = radius of atom

Put the value into the formula

[tex]V'=\dfrac{4\pi\times(1\times10^{-15})^3}{3}[/tex]

[tex]V'=4.18\times10^{-45}\ m^3[/tex]

(c). We need to calculate the percentage of the volume of the atom that is occupied by the nucleus

[tex]percentage=\dfrac{V'}{V}\times100[/tex]

Put the value into the formula

[tex]percentage=\dfrac{4.18\times10^{-45}}{6.23\times10^{-31}}\times100[/tex]

[tex]percentage=6.70\times10^{-13}[/tex]

Hence, (a). The volume of the atom is [tex]6.23\times10^{-31}\ m^3[/tex]

(b). The volume of the nucleus is [tex]4.18\times10^{-45}\ m^3[/tex]

(c). The percentage of the volume of the atom that is occupied by the nucleus is [tex]6.70\times10^{-13}[/tex]