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28-01-2020
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[tex] - 6(4 - \times ) \leqslant - 4( \times + 1)[/tex]

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28-01-2020

Assuming [tex]\times=x[/tex] which latex-wise is not true but ok.

We have the inequality that means the solution will be an interval.

[tex]

-6(4-x) \leq -4(x+1) \\

-24+6x \leq -4x-4 \\

10x \leq 20 \\

x \leq 2 \Longrightarrow x\in (-\infty, 2]

[/tex]

Hope this helps.

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