Respuesta :
Answer:
See explanation!
Step-by-step explanation:
The remaining question reads:
Part A: Write a system of equations to represent the situation. Let x = hours and y = widgets.
Part B: How much time does it take for Tamara and Jason to produce the same number of widgets?
Part C: How many widgets will Tamara and Jason have produced?
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To solve this problem we can construct an linear algebraic expression for each person, principally denoted as:
[tex]y=ax+c[/tex]
where
[tex]y[/tex] :is our dependent variable (which is a function of [tex]x[/tex])
[tex]x[/tex] :is our independent variable
[tex]a[/tex] :is the slope
[tex]c[/tex] :is the y-intercept constant value (if any present)
Part A: Write a system of equations to represent the situation. Let x = hours and y = widgets.
Tamara
Has already made 20 widgets and produces at a rate of 8 widgets per hour thus here [tex]c=20[/tex] and [tex]a=8[/tex], so Tamara's equation reads:
[tex]y_{T}=8x+20[/tex]
Jason
Has not produced any widgets yet and produces at a rate of 12 widgets per hour thus here [tex]c=0[/tex] and [tex]a=12[/tex], so Jason's equation reads:
[tex]y_{J}=12x[/tex]
So the system of equations will be
[tex]y_{T}=8x+20\\y_{J}=12x[/tex]
Part B: How much time does it take for Tamara and Jason to produce the same number of widgets?
Since we want to find the amount of time (i.e. the value of [tex]x[/tex] ) it takes for both of them to produce the same number of widgets we can just equate the two equations ans solve for [tex]x[/tex] as follow:
[tex]y_{T}=y_{J}\\8x+20=12x\\8x-12x=-20\\-4x=-20\\x=\frac{-20}{-4}\\ x=5[/tex]
So it takes them 5 hours to produce the same amount of widgets.
Part C: How many widgets will Tamara and Jason have produced?
Now we can simply plug in the value of [tex]x=5[/tex] in any of the two equations (i.e. either for Tamara or Jason) to find the number of widgets produced.
[tex]y_{T}=8(5)+20=40+20=60[/tex]
So in a time-space of 5 hours Each will have produced 60 widgets and in total will be 60+60 = 120 widgets.