Answer:
Step-by-step explanation:
98÷14
=7
686÷98
=7
4 802÷686
=7
33 614÷4 802
=7
Then the common ratio q for this sequence is 7
recursive formula : an+1 = q×an = ?
an= a1 × qⁿ⁻¹
=2×7ⁿ⁻¹
an+1 = q×an
= 7×(2×7ⁿ⁻¹)
= 2×7ⁿ
Answer: The formular for this sequence is AR^n-1 (that is, A multiplied by R{raised to the power of n minus 1} )
Step-by-step explanation:This is a geometric progression in which every term is calculated by multiplying each previous term by a common ratio.
The common ratio here is 7, which is derived as
14/2, or 98/14, or 686/98, or 4802/686...
In simply put, R is derived as Tn/Tn-1, where Tn is the nth term and Tn-1 is the previous term.
Therefore the formular for this progression is given as
AR^n-1
Where A = 2, R = 7 and n = the nth term.
