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The total number of offspring from a monohybrid cross was found to be 600 and the expected phenotypic ratio was 1:2:1. For the purposes of a X2-test, what would the calculated values of E be?

Respuesta :

namordu

Answer:

150 AA, 300 Aa and 150 aa

Explanation:

The expected phenotypic ratio of 1:2:1 means that we expect:

  • 1/4 of the offspring to be AA
  • 2/4 of the offspring to be Aa
  • 1/4 of the offspring to be aa

If the total number of offspring was 600, then the E values would be:

  • 1/4 × 600 = 150 AA
  • 2/4 × 600 = 300 Aa
  • 1/4 × 600 = 150 aa