Answer:
The work done by the force is 109.5 Joules.
Explanation:
It is given that,
Mass of the object, m = 3 kg
Speed of the object, v = 5 m/s
Force applied on the object, F = 12 N
Distance covered by the object, d = 6 m
The work done by this force is given by the sum of kinetic energy and potential energy as per work energy theorem as :
[tex]W=K+P[/tex]
[tex]W= \dfrac{1}{2}mv^2+Fd[/tex]
[tex]W=\dfrac{1}{2}\times 3\times (5)^2+12\times 6[/tex]
W = 109.5 Joules
So, the work done by the force is 109.5 Joules. Hence, this is the required solution.
