contestada

A hydrogen atom in an excited state emits a photon of frequency ν = 3.084 x 1015 s-1. If the electron returns to the ground state, in which level was it before the photon was emitted?

Respuesta :

pstnonsonjoku

The initial energy level is n=3.

Using the formula;

λ = c/f

  • λ= wavelength  of the photon
  • h = Plank's constant
  • f = frequency

λ =3 × 10^8 m/s /  3.084 x 10^15 s-1

λ = 9.73 × 10^-7 m

Again;

1/λ = 1.097 × 10^7 (1/n^2 final - 1/n^2 initial)

9.73 × 10^-8= 1.097 × 10^7 (1/1^2 - 1/n^2 initial)

9.73 × 10^-8/1.097 × 10^7 = (1/1^2 - 1/n^2 initial)

0.887 =  (1/1^2 - 1/n^2 initial)

1/n^2 initial = 1 - 0.887

n initial = 3

Learn more about energy levels: https://brainly.com/question/24373411

Otras preguntas