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A child bounces in a harness suspended from a door frame by three parallel elastic bands. (a) If each elastic band stretches 0.210 m while supporting a 6.80 kg child, what is the force constant for each elastic band?

Respuesta :

Answer:

spring constant of the spring will be equal to 317.33 N/m

Explanation:

We have given mass of the child m = 6.80 kg

Spring is stretched by length of 0.210 m . so x = 0.210 m

Acceleration due to gravity [tex]g=9.8m/sec^2[/tex]

Force on the child will be equal to [tex]W=mg[/tex]

This force will be balanced by spring force

And spring force is equal to F = Kx

So kx = mg

[tex]k\times 0.210=6.80\times 9.8[/tex]

k = 317.33 N /m

So spring constant of the spring will be equal to 317.33 N/m

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