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Diagram 1 shows a triangle with feet of length 4y cm and height (y + 5) cm. Diagram 2 shows a square with a length of y cm. Given the area of ​​the triangle exceeds the rectangle by 39 cm². Calculate the perimeter of the two diagrams.​

Diagram 1 shows a triangle with feet of length 4y cm and height y 5 cm Diagram 2 shows a square with a length of y cm Given the area of the triangle exceeds the class=

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devishri1977

Answer:

Step-by-step explanation:

Diagram 1

Area = b*h/2 = 4y*(y+5)/2 = 2y*(y+5)= 2y² + 10y

Diagram 2

Area = side*side = y * y = y²

the area of ​​the triangle exceeds the rectangle by 39 cm².

2y² + 10y - y² = 39

y² + 10y = 39

y² + 10y -39 = 0

y² +13y - 3y - 3*13 = 0

y(y+13) -3(y+13)=0

(y+13)(y-3) = 0

y  + 13 = 0  will not come as length couldn't be in negative

y - 3 = 0

y = 3 cm

Diagram 2:

Perimeter = 4*side = 4*y = 4*3 = 12 cm

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