Answer:
The volume of required foam is 0.1 cm³
Step-by-step explanation:
Given as :
The volume of box = v = 113.14 cm³
The radius of the crystal ball = r = 3 cm
Let The volume of required foam = V cm³
According to question
Volume of crystal ball = [tex]\dfrac{4}{3}[/tex] × π × radius³ where π = 3.14
i.e Volume of ball = [tex]\dfrac{4}{3}[/tex] × π × 3³
Or, Volume of ball = [tex]\dfrac{4}{3}[/tex] × π × 27
Or, Volume of ball = [tex]\dfrac{4}{3}[/tex] × 3.14 × 27
Or, Volume of ball = 4 × 3.14 × 9
Or, Volume of ball = 113.04 cm³
Again
∵ volume of crystal ball = v' = 113.04 cm³
So , The volume of required foam = volume of box - volume of crystal ball
Or, V = v - v'
Or, V = 113.14 cm³ - 113.04 cm³
∴ V = 0.1 cm³
So, The volume of required foam = V = 0.1 cm³
Hence, The volume of required foam is 0.1 cm³ . Answer
