Answer:
32.3 feet
Step-by-step explanation:
Let BC=32 feet
AC=60.5 feet
The angle between side BC and AC=45-25=20 degrees
We have to find the distance traveled by player to get to the ball.
Cosine law: [tex]c^2=a^2+b^2-2ab Cos\theta[/tex]
Using Cosine law
[tex]c=\sqrt{(32)^2+(60.5)^2-2(32)(60.5)Cos 20^{\circ}}[/tex]
[tex]c=\sqrt{(32)^2+(60.5)^2-2(32)(60.5)(0.9396)}[/tex]
[tex]c=32.3 feet[/tex]
Hence, he travel 32.3 feet to get to the ball.
