Answer:
[tex]g'=0.6131\ m.s^{-2}[/tex]
Explanation:
The gravity of earth at the north pole is nearly [tex]9.81\ m.s^{-2}[/tex]
Now for the gravity of the earth at a height 3 times the earth radii above the earth surface at the north pole can be given as:
[tex]g'=g.\frac{R^2}{(R+h)^2}[/tex]
[tex]g'=9.81\times \frac{64000000^2}{(64000000+3\times 64000000)^2}[/tex]
[tex]g'=0.6131\ m.s^{-2}[/tex]
