Let us use the principle given in the relation of density as a function of mass and volume, but this time we will reorganize it in terms of mass so that said displaced mass is equivalent to the density of water by the volume of the stone , So,
[tex]\rho = \frac{m}{V} \rightarrow m = \rho V[/tex]
Where,
[tex]\rho[/tex]= Density
m = mass
V = Volume
Replacing,
m = 5500*0.25
m = 1375kg
Therefore the mass of water it displaces is 1375kg
