Answer:
For the simplicity, I will denote the direction along the inclined plane as x-direction, and the perpendicular direction as y-direction.
A. Wrong. The maximum possible value of the force of static friction is
[tex]F_s = \mu_smg\cos(\theta)[/tex]
As the angle is increased, cosine component is decreases, so the maximum value of the static friction force decreases.
B. Correct. The force of static friction (not the maximum value) increases, as the x-component of the weight of the block increases with the angle.
[tex]w_x = mg\sin(\theta)[/tex]
C. Wrong. As I explained in part A the maximum value of the force of static friction decreases.
D. Wrong. The force of static friction (not the maximum value) increases as explained in part B.
E. Wrong. As explained in part B, the force of static friction increases.
F. Correct. As I explained in part A, the maximum value of the force of static friction decreases.
