Answer:
Explanation:
Given
Current in two wires
[tex]I_1=2 A[/tex]
[tex]I_2=4 A[/tex]
Magnetic Force per unit length is given by
[tex]\frac{F}{l}=\frac{\mu _0I_1I_2}{2\pi r}[/tex]
where [tex]\mu _0=space\ permittivity [/tex]
r=radial distance between wires
[tex]F_{12}=5\times 10^{-4} N/m[/tex]
Force on two wires will be equal in magnitudes but opposite in direction so Force on wire 1 duet o wire 2
[tex]F_{12}=5\times 10^{-4} N/m[/tex]
