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A 91 kg man in a 5.3-kg chair tilts back so that all the weight is balanced on two legs of the chair. Assume that each leg makes contact with the floor over a circular area with a radius of 1.1 cm, and find the pressure exerted by each leg on the floor.

Respuesta :

Khoso123

Answer:

P=1.173×10⁶ pa

Explanation:

given  data

m = 91 kg

r = 1.1 cm = 0.011 m

then

F = mg

"F=mg is the equation for the force of gravity. where, F is the force pulling objects toward the Earth. m is the mass of the object. g is the acceleration due to gravity; this number is a constant for all masses of matter."

&

A = πr² + πr² = 2πr²

so

P = F/A

where P is pressure F is force and A is area

P=mg/(2πr²)

P=91*9.8/{2π(0.11)²}

P=1173606.4 pa

P=1.173×10⁶ pa

is the pressure exerted by each leg

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