Answer:
v = 13.79 m/s
Explanation:
given,
mass of ball = 110 g
height = 11 m
ball is released from = 1.3 m
minimum speed = ?
using conservation of energy
Potential energy is conserved in the form of kinetic energy
[tex]P E =KE[/tex]
[tex]m g h= \dfrac{1}{2}mv^2[/tex]
[tex]v^2 = 2 g h[/tex]
[tex]v=\sqrt{2 g h}[/tex]
[tex]v=\sqrt{2\times 9.8 \times (11-1.3)}[/tex]
[tex]v=\sqrt{2\times 9.8 \times 9.7}[/tex]
[tex]v=\sqrt{190.12}[/tex]
v = 13.79 m/s
