Answer:
D. 2.40 atm
Explanation:
At constant temperature and number of moles, using Boyle's law
[tex] {P_1}\times {V_1}={P_2}\times {V_2}[/tex]
Given ,
V₁ = 0.250 L
V₂ = 0.125 L
P₁ = 1.20 atm
P₂ = ? atm
Using above equation as:
[tex]{P_1}\times {V_1}={P_2}\times {V_2}[/tex]
[tex]{1.20\ atm}\times {0.250\ L}={P_2}\times {0.125\ L}[/tex]
[tex]{P_2=\frac{{1.20}\times {0.250}}{0.125}\ atm[/tex]
[tex]{P_2}=2.40 atm[/tex]
Answer:- D. 2.40 atm
