Answer:
100%
Explanation:
Let PP represent homozygous dominant trait for widow's peak &
Let Pp represent an individual heterozygous for widow's peak.
If both traits cross together; the chance that the child will have a widow's peak = ???
i.e PP × Pp
| P | P
P | PP | PP
p | Pp | Pp
The progeny are: ( PP, PP, Pp, Pp)
When a trait is dominant, only one allele is required for the trait to be observed. A dominant allele will mask a recessive allele, if present.
From our question, one parent is homozygous dominant (PP) and the other is heterozygous (Pp): therefore all their offspring will be two homozygous dominant (PP) and two heterozygous (Pp) and they will all possess a widow’s peak.
Therefore, the chance that a child will have a widow's peak = 100%
