Respuesta :
Answer:
No, the truck will not cross the barrier.
The closeness of the truck to the barrier is of 21.875 m
Solution:
As per the question:
Velocity of the truck, v = 25.0 m/s
Acceleration of the truck, a = - 4 [tex]m/s^{2}[/tex]
Now,
Since, the barrier at a distance of 100 m. Thus in order to check whether the truck hit the barrier or not, we will see the distance, d it covers by using the kinematic eqn:
[tex]v'^{2} = v^{2} + 2ad[/tex]
Final velocity, v' = 0 m/s
Initial velocity = v
Now,
[tex]0^{2} = 25^{2} + 2\times -4d[/tex]
[tex]- 8d = - 625[/tex]
d = 78.125 m
Thus the truck will not cross the barrier.
Distance between the barrier and the truck:
100 - 78.125 = 21.875 m
Answer:
No.
x= 21.875 m .
Explanation:
Given that
Speed of the truck ,u = 25 m/s
Deceleration ,a = - 4 m/s²
The distance of barrier from truck ,d= 100 m
The distance travel by truck when driver apply the brake = s m
The final speed of the truck will be zero.
v= 0 m/s
We know that
v²= u² + 2 a s
0²= 25² - 2 x 4 x s
625 = 8 s
s= 78.125 m
The distance s is less than the distance d,Therefore the truck will not hit the barrier.
The distance from the barrier where the truck will be stop ,x= 100 - 78.125 m
x= 100 - 78.125 m
x= 21.875 m
