Explanation:
[tex]\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}[/tex]
We are given:
Mass of liquid = 23.46 g
Volume occupied by the ring = [tex]2.25 cm^3[/tex]
Density of gold ring = D
[tex]D=\frac{23.46 g}{2.25 cm^3}=10.43 g/cm^3[/tex]
Original density of gold = [tex]19.3 g/cm^3[/tex]
[tex]10.43 g/cm^3<19.3 g/cm^3[/tex]
We will tell the buyer that gold ring purchased from him is too adulterated with other metals which have reduced its density indication that it is an artificial gold ring.
