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A Las Vegas handicapper can correctly predict the winning professional football team 70% of the time. The probability that she is wrong in her next prediction is 30%. For the same handicapper, find the probability that she is correct in each of her next two predictions.

Respuesta :

pedrocarratore

Answer:

0.49 or 49%

Step-by-step explanation:

The probability of the handicapper correctly predicting a single game, P(C), is 0.7, therefore, the probability of that same handicapper being correct in each of her next two predictions, P(2C) is:

[tex]P(2C) = P(C)^2\\P(2C) = 0.7^2\\P(2C) = 0.49[/tex]

The probability of her being correct in each of her next two predictions is 0.49 or 49%

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