Respuesta :
Answer:
The heat rejected is 146J.
The work done by the engine is 54J.
The thermal efficiency is 0.27
Explanation:
The efficiency of the carnot engine, which is working between a hot source at a temperature [tex]T_{1}[/tex] and a cold source at a temperature [tex]T_{2}[/tex], is given by:
[tex]Efficiency=1-\frac{T_{2}}{T_{1}}[/tex]
The normal boiling point of water is 373 K. ([tex]T_{1}[/tex])
The temperature of triple point of water is 273.15 K ([tex]T_{2}[/tex])
[tex]Efficiency=1-\frac{273.15}{373}=0.27[/tex]
[tex]Efficiency=\frac{Work\:done}{Heat\:absorbed}=\frac{Work\:done}{200}=0.27\\Work\:done=0.27\times200=54J\\Work\:done=Heat\:absorbed-Heat\:rejected\\Heat\:rejected=Heat\:absorbed-Work\:done=200-54=146J[/tex]
