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a fish tank in the shape of a rectangular prism measures 100 x 60 x 40/The water level reached the midpost of the base (50cm mark) when the tank was tilted to rest on a 60cm edge. What would be the depth of the water, if the tank is returned to its horizontal position (resting on a 60x100 base)?

Respuesta :

Answer:

Step-by-step explanation:

volume of water

[tex]=\frac{1}{2}*50*40*60=60000 ~cm^3[/tex]

when the base is 100×60

let h be depth of water.

100×60×h=60000

h=60000/6000=10 cm.

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