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A model airplane with mass 0.741 kg is tethered to the ground by a wire so that it flies in a horizontal circle 30.5 m in radius. The airplane engine provides a net thrust of 0.804 N perpendicular to the tethering wire.
Find the magnitude of the torque the net thrust produces about the center of the circle.

Respuesta :

davidlcastiblanco

Answer:

The magnitude of torque is τ = 24.522 N*m^2

Explanation:

To find the magnitude of the torque can use the equation of the force produce by the airplane so:

τ = F * d

τ = 0.804 N * 30.5 m

τ = 24.522 N*m

Check:

Find the acceleration

I = m*r^2=0.741kg*(30.5m)^2

I = 689.32 kg*m^2

τ = I*a_c

a_c = τ /I = 24.522 N*m^2 / 689.32 kg*m^2

a_c = 0.0355 m/s^2

τ = 0.0355 m/s^2 * 689.32 kg*m^2

τ = 24.522 N*m^2

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