Answer:
The standard deviation of this sampling distribution is 3.07
Explanation:
There are n = 10 samples
Mean: [tex]\frac{\sum x_{i}}{n}[/tex] = (10 + 9 + 11 + 7 + 3 + 12 + 8 + 4 + 6 + 11) / 10 = 8.1
Variance: s^2 = [tex]\frac{\sum {(x_{i} - mean)^{2}}}{n-1}[/tex]
= [(10 - 8.1)^2 + (9 - 8.1)^2 + (11 - 8.1)^2 + (7 - 8.1)^2+ (3 - 8.1)^2+ (12 - 8.1)^2] + (8 - 8.1)^2+ (4 - 8.1)^2+ (6 - 8.1)^2+ (11 - 8.1)^2] / 9
= 9.43
Standard deviation: s = [tex]\sqrt{s^2}[/tex] = [tex]\sqrt{9.43}[/tex] = 3.07
