An 8.7 g bullet is accelerated in a rifle barrel 105 cm long to a speed of 465 m/s. Use the work-energy theorem to find the average force exerted on the bullet while it is being accelerated. Answer in units of N.

Respuesta :

Answer:896 N

Explanation:

Given

mass of bullet [tex]m=8.7 gm[/tex]

Length of barrel [tex]d=105 cm=1.05 m[/tex]

final velocity [tex]v=465 m/s[/tex]

initial velocity [tex]u=0 m/s[/tex]

Work done by all the forces is equal to change in kinetic Energy

[tex]F\cdot d=\frac{1}{2}\times mv^2-0[/tex]

[tex]F_{avg}\times 1.05=\frac{1}{2}\times 8.7\times 10^{-3}\times 465^2[/tex]

[tex]F_{avg}=\frac{0.5\times 8.7\times 10^{-3}\times 465^2}{1.05}[/tex]

[tex]F_{avg}=895.789 Na\pprox 896 N[/tex]