Answer:
p value =0.024
Step-by-step explanation:
Given that a sample of 46 copper wires had a mean resistance of 1.03 mΩ with a standard deviation of 0.1 mΩ
Let μ represent the mean resistance of copper wires of this type.
[tex]H_0: \mu \leq 1\\H_a: \mu >1[/tex]
(one tailed test )
Sample size n = 46
[tex]\bar x = 1.03\\s = 0.1\\Std error = \frac{0.1}{\sqrt{46} } \\=0.0147[/tex]
Mean difference = 0.03
Test statistic t = mean difference /std error
=2.035
df = 45
p value for one tailed=0.023884
