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A large uniform chain is hanging from the ceiling, supporting a block of mass 46 kg. The mass of the chain itself is 19 kg, and the length of the chain is 1.9 m. The acceleration of gravity is 9.81 m/s 2 . Find the tension in the chain at the point where the chain is supporting the block. Answer in units of N.

Respuesta :

Answer:

T = 451.26 N

Explanation:

It is given that,

The mass of block, m = 46 kg

Mass of the chain, m' = 19 kg

Length of the chain, l = 1.9 m

Let T is the the tension in the chain at the point where the chain is supporting the block. It is clearly equal to the product of mass and acceleration.

[tex]T=mg[/tex]

[tex]T=46\ kg\times 9.81\ m/s^2[/tex]

T = 451.26 N

So, the tension in the chain at the point where the chain is supporting the block is 451.26 N. Hence, this is the required solution.

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