The final volume of the gas is 144.25 L
Explanation:
For an ideal gas kept at constant pressure, the work done by the gas on the surroundings is given by
[tex]W=p\Delta V = p(V_f - V_i)[/tex]
where
p is the pressure of the gas
[tex]V_i[/tex] is the initial volume
[tex]V_f[/tex] is the final volume
For the gas in the cylinder in this problem,
p = 2.00 atm
[tex]V_i = 0.250 L[/tex]
And we also know the work done,
W = 288 J
So we can solve the equation for [tex]V_f[/tex], the final volume:
[tex]V_f = V_i + \frac{W}{p}=0.250 + \frac{288}{2.00}=144.25 L[/tex]
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