The volume that would be occupied by oxygen gas is equal to 10 Liters
Given the following data:
Mass = 4.8 g
Pressure = 0.50 atm
Temperature = 133°C to K = [tex]273+133 =406\;K[/tex]
Scientific data:
Molar mass of oxygen gas = 32 g/mol.
Ideal gas constant, R = 0.0821L⋅atm/mol⋅K
To determine the volume that would be occupied by oxygen gas:
First of all, we would determine the number of moles of oxygen gas present.
[tex]Number\;of\;moles = \frac{mass}{molar\;mass}\\\\Number\;of\;moles = \frac{4.8}{32}[/tex]
Number of moles = 0.15 moles
Now, we can find the volume of oxygen gas by the ideal gas law equation;
[tex]V = \frac{nRT}{P} \\\\V=\frac{0.15 \times 0.0821 \times 406}{0.5} \\\\V=\frac{4.99989}{0.5}[/tex]
Volume = 10 Liters
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