Answer:
there are two solutions:
a) [tex]y=\frac{-6+2\sqrt{6} }{5}[/tex], and
b) [tex]y=\frac{-6-2\sqrt{6} }{5}[/tex]
Step-by-step explanation:
In the equation: [tex](5y+6)^2=24[/tex], since a perfect square with the unknown "y" is isolated on the left of the equal sign, we start by applying the square root on both sides of the equality, and then on isolating the unknown:
[tex](5y+6)^2=24\\\sqrt{(5y+6)^2} =+/-\sqrt{24} \\(5y+6)=+/-\sqrt{6*4} \\(5y+6)=+/-2\sqrt{6}\\5y=-6+/-2\sqrt{6}\\y=\frac{-6+/-2\sqrt{6} }{5}[/tex]
Therefore there are two solutions:
a) [tex]y=\frac{-6+2\sqrt{6} }{5}[/tex], and
b) [tex]y=\frac{-6-2\sqrt{6} }{5}[/tex]
Answer: A
[tex]y=\frac{-6+2\sqrt{6} }{5} \\y=\frac{-6-2\sqrt{6} }{5}[/tex]
Step-by-step explanation:
just did this
