Answer:
1697.41 cubic meters.
Step-by-step explanation:
See the attached figure of the side triangle of the solid.
Let Δ ABC is the side triangle which is equilateral triangle, so AB = AC = BC = 14 m.
We have to find its area.
Let altitude AD divides BC into two equal parts BD = DC = 7 m
Now, Δ ADC is right triangle and AD² = AC² - DC² = 14² - 7² = 147
{Applying Pythagoras Theorem}
So, AD = 12.124 m
So, the area of the triangle is [tex]\frac{1}{2} \times BC \times AD = 0.5 \times 14 \times 12.124 = 84.87[/tex] sq. m.
Therefore, volume of the solid given in the figure is (84.87 × 20) = 1697.41 cubic meters. (Answer)
