A feather is dropped onto the surface of the moon. How far will the feather have fallen if it reaches the surface in 9.00 seconds?

Given: g on moon = –1.63 meters/second2

Respuesta :

Answer: 66m

Explanation:

Using equation of motion;

S = ut + 1/2gt²

u = 0 ( initial velocity wasn't given)

t = 9s

g = 1.63m/s²

S = 0 + 0.5*(1.63)*(9²)

S= 66.015m