Answer:
P-value of the test statistic is 2.499
Explanation:
given data:
size sample is 24
sample mean is 414 gm
standard deviation is 15
Null hypotheis is
[tex]H_0: \mu = 420 gm[/tex]
[tex]H_1 \mu< 420[/tex]
level of significance is 0.01
from test statics
[tex]t = \frac{\hat x - \mu}{\frac{s}{\sqrt{n}}}[/tex]
degree od freedom is = n -1
df = 24 -1 = 13
[tex]t = \frac{414 - 420}{\frac{15}{\sqrt{24}}}[/tex]
t = -1.959
from t table critical value of t at 0.1 significane level and 23 degree of freedom is 2.499
