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Mr. Walker is looking at the fundraiser totals for the last five years.

A 2-column table with 5 rows. The first column is labeled year with entries 1, 2, 3, 4, 5. The second column is labeled total (in dollars) with entries 896, 925, 880, 963, 914.
How does the mean of the totals compare to the median?

The median is $1.60 greater than the mean.
The mean is $1.60 greater than the median.
The median is $2.82 greater than the mean.
The mean is $2.82 greater than the median

Respuesta :

The mean is $1.60 greater than the median.

Step-by-step explanation:

Here, the given data is :    896, 925, 880, 963, 914.

Calculating mean of the given data:   MEAN = [tex]\frac{\textrm{Sum of the observations}}{\textrm{Number of observations}}[/tex]

= [tex]\frac{896 + 925 +  880+ 963+  914}{5}  = \frac{4578}{5}  = 915.6[/tex]

Hence, the mean of the given data is $ 915.6

Now, for median, arrange the data in the ascending order.

880, 896, 914 ,925,  963  is the ascending order.

Here, 914 is the MIDDLE TERM.

Hence, MEDIAN  of the given data is $ 914.

By comparing mean = $ 915.6 and median = $ 914, we can see that

The mean is $1.60 greater than the median.

Answer:

B)The mean is $1.60 greater than the median.

Step-by-step explanation:

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