The circle below is centered at the point (8,4) and has a radius of length 4.
What is its equation?
O A. (x-4)2 + (y + 8)2 = 4
O B. (x-8)2 + (y-4)2 =
16
O C. (x-4)2 + (7-8)2 =
10
42
O D. (x+8)2 + (9-4)2 =
16
SUBMIT

[tex]\textup{The equation of a circle is given by:}\\$c = \sqrt{{(x-h)}^2 + {(y-k)}^2} = r^2$\\\textit{where $(h,k)$ represents the centre of the circle and $r$ the radius.}\\\textup{Given the centre of the circle is $(8,4)$ and radius is $4$.}$ \therefore $ We have $c = \sqrt{{(x-8)}^2 + {(y-4)}^2} = 4^2$$\implies {(x-8)}^2 + {(y-4)}^2 = 16$[/tex]

The circle below is centered at the point (8,4) and has a radius of length 4. What is its equation? O A. (x-4)2 + (y + 8)2 = 4 O B. (x-8)2 + (y-4)2 = 16 O C. (x-4)2 + (7-8)2 = 10 42 O D. (x+8)2 + (9-4)2 = 16 SUBMIT

Respuesta :

Otras preguntas

The circle below is centered at the point (8,4) and has a radius of length 4.
What is its equation?
O A. (x-4)2 + (y + 8)2 = 4
O B. (x-8)2 + (y-4)2 =
16
O C. (x-4)2 + (7-8)2 =
10
42
O D. (x+8)2 + (9-4)2 =
16
SUBMIT