The voltage is presented by the equation V = IR where V
is voltage in V, I is current in amperes ad R is resistance in ohms. If a
platinum wire has a resistance of 15 Ω and is connected across the terminals of
a 3.0 V flashlight battery, the current can be solved through V= IR, 3.0 V = I
(15 Ω), and the current is 0.2 A.
