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Racing greyhounds are capable of rounding corners at very high speeds. A typical greyhound track has turns that are 45-m-diameter semicircles. A greyhound can run around these turns at a constant speed of 15 m/s. What is its acceleration in m/s2
and in units of g?

Respuesta :

Explanation:

It is given that,

Diameter of the semicircle, d = 45 m

Radius of the semicircle, r = 22.5 m      

Speed of greyhound, v = 15 m/s

The greyhound is moving under the action of centripetal acceleration. Its formula is given by :

[tex]a=\dfrac{v^2}{r}[/tex]

[tex]a=\dfrac{(15)^2}{22.5}[/tex]

[tex]a=10\ m/s^2[/tex]

We know that, [tex]g=9.8\ m/s^2[/tex]

[tex]a=\dfrac{10\times g}{9.8}[/tex]

[tex]a=1.02\ g[/tex]

Hence, this is the required solution.                                              

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