Respuesta :
Answer:
Option 4 - [tex]x=\pm5\sqrt{2}[/tex]
Step-by-step explanation:
Given : Quadratic equation [tex]50-x^2=0[/tex]
To find : What are the solution(s) to the quadratic equation ?
Solution :
Step 1 - Write the quadratic equation,
[tex]50-x^2=0[/tex]
Step 2 - Subtract 50 both side,
[tex]x^2=50[/tex]
Step 3 - Taking root both side,
[tex]x=\pm\sqrt{50}[/tex]
[tex]x=\pm\sqrt{2\times 5\times5}[/tex]
[tex]x=\pm5\sqrt{2}[/tex]
Therefore, the solution of the equation is [tex]x=\pm5\sqrt{2}[/tex]
So, option 4 is correct.
Answer:
C) x = ±5Plus or minus 5 StartRoot 2 EndRoot on ed!!!
Step-by-step explanation: