Respuesta :
Answer:
[tex]11.4333 m.s^{-2}[/tex]
Explanation:
Given:
- actual weight on the earth, m = 150 lbs × g = 68.0389 kgf
- apparent weight in the spacecraft, M = 175 lbs × g = 79.3787 kgf
∵The apparent weight increases it means that the spacecraft is accelerating in the direction opposite to the gravity and having the value greater than 9.8[tex]m.s^{-2}[/tex]
DIfference in the weight,
[tex]F= M.g - m.g[/tex]
[tex]F= (79.3787 -68.0389 )\times 9.8[/tex]
[tex]F=11.3398\times 9.8\\F=111.13004 N[/tex]
This difference in weight is due to the difference in acceleration of the gravity and the spacecraft.
So, the quantity of acceleration responsible for this difference in weight:
[tex]F=m.\Delta a[/tex].................(1)
where:
m= mass of the body being accelerated
[tex]\Delta a[/tex]= difference in the acceleration
from eq. (1)
[tex]111.13004 = 68.0389 \times \Delta a[/tex]
[tex]\Delta a=1.6333 m.s^{-2}[/tex]
∴The actual accelerationof the spacecraft:
a=[tex]g+\Delta a[/tex]
a = 9.8 + 1.6333
a = [tex]11.4333 m.s^{-2}[/tex]
