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A 4.0 kg bucket of water is raised from a well
by a rope.
The acceleration of gravity is 9.81 m/s?.
If the upward acceleration of the bucket is
2.8 m/s², find the force exerted by the rope
on the bucket of water.
1. 69.658
2. 52.84
3. 85.318
4. 70.86
5. 84.429

Respuesta :

MathPhys

Explanation:

Draw a free body diagram of the bucket.  There are two forces:

Tension force T pulling up.

Weight force mg pulling down.

Sum of forces in the y direction:

∑F = ma

T − mg = ma

T = mg + ma

T = m (g + a)

Given m = 4.0 kg, g = 9.81 m/s², and a = 2.8 m/s²:

T = (4.0 kg) (9.81 m/s² + 2.8 m/s²)

T = 50.44 N

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