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Write a balanced, net ionic equation for the precipitation reaction of CaCl₂ and Cs₃PO₄ in an aqueous solution. Remember to include the proper physical states and charges of ions. When writing ions, if a charge number is not "1", place the charge number before the charge sign. If a charge sign is "1", do not include the charge number in the formula.

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Answer:

3 Ca²⁺(aq) + 2 PO₄³⁻(aq) ⇄ Ca₃(PO₄)₂(s)

Explanation:

We can write 3 kinds of equations:

  • Molecular equation: includes all species in the molecular form. It is useful to write this one first so balancing is easier.
  • Full ionic equation: includes all ions and species that do not dissociate in water.
  • Net ionic equation: includes only ions that participate in the reaction (not spectator ions) and species that do not dissociate in water.

The reaction between CaCl₂ and Cs₃PO₄ in an aqueous solution is a precipitation (solid Ca₃(PO₄)₂ is formed) and a double displacement one.

Molecular equation

3 CaCl₂(aq) + 2 Cs₃PO₄(aq) ⇄ Ca₃(PO₄)₂(s) + 6 CsCl(aq)

Full ionic equation

3 Ca²⁺(aq) + 6 Cl⁻(aq) + 6 Cs⁺(aq) + 2 PO₄³⁻(aq) ⇄ Ca₃(PO₄)₂(s) + 6 Cs⁺(aq) + 6 Cl⁻(aq)

Net ionic equation

3 Ca²⁺(aq) + 2 PO₄³⁻(aq) ⇄ Ca₃(PO₄)₂(s)

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