Answer:
The force bumper at 0.200m
F=2722.5 N
Explanation:
Using the energy theorem of work
[tex]W=K_{f}- K_{i}[/tex]
W=ΔK
W=F*d
ΔK=[tex]\frac{1}{2}*m*v_{f} ^{2} -\frac{1}{2}*m*v_{i} ^{2}[/tex]
[tex]v_{i} =0[/tex]
ΔK=F*d=[tex]\frac{1}{2}*m*v_{f} ^{2} -\frac{1}{2}*m*v_{i} ^{2}[/tex]
[tex]F*d=\frac{1}{2}*m*0 ^{2}- \frac{1}{2}*m*v_{i} ^{2}\\F*d=-\frac{1}{2}*m*v_{i} ^{2}=\frac{1}{2}*900kg*(1.1\frac{m}{s})^{2}\\F*d=544.5\frac{kg*m}{s^{2}}\\ F=\frac{544.5\frac{kg*m}{s^{2}}}{0.2m} \\F=2722.5 N[/tex]
